eucilds division lemma problem

Asked by vshrikanth | 15th Apr, 2010, 04:59: PM

Expert Answer:

Any odd integer is of the form 2n+1 where n is any integer and even integer =2n for any integer n

Let 2n+1 and 2m+1 are any odd positive integers

So 2n+1 +2m+1 = 2(n+m)+2 =2(n+m+1)  which is even number

Answered by  | 20th Apr, 2010, 10:15: AM

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