Equation to normal.

Asked by  | 3rd Mar, 2010, 09:16: PM

Expert Answer:

y = x2/4

Slope of tangent = dy/dx = x

Slope of normal = -1/(dy/dx) = -1/x = -1/1 = -1

Slope of normal at given point (1,2) is -1.

Regards,

Team,

TopperLearning

Answered by  | 4th Mar, 2010, 05:39: AM

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