Equation to normal.
Asked by | 3rd Mar, 2010, 09:16: PM
y = x2/4
Slope of tangent = dy/dx = x
Slope of normal = -1/(dy/dx) = -1/x = -1/1 = -1
Slope of normal at given point (1,2) is -1.
Answered by | 4th Mar, 2010, 05:39: AM
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