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CBSE Class 12-science Answered

Equation to normal.
Asked by | 03 Mar, 2010, 09:16: PM
answered-by-expert Expert Answer

y = x2/4

Slope of tangent = dy/dx = x

Slope of normal = -1/(dy/dx) = -1/x = -1/1 = -1

Slope of normal at given point (1,2) is -1.

Regards,

Team,

TopperLearning

Answered by | 04 Mar, 2010, 05:39: AM
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