equal volumes of two immiscible liquids of densities p and 2p are filled in a vessel. two small holes are drilled at depths h/2 and 3h/2 from the surface of the lighter liquid. if v1 and v2 are the speed of efflux at these two holes, then (v2/v1)^2 is

Asked by  | 14th Nov, 2012, 10:28: AM

Expert Answer:

 
Here,
v1=?(2gh/2)=?(gh)
v2:
if we consider two points, ie one hole and the other point at the same level of the hole:
from bernoulli's pr:
P+pgh+2pgh/2+0=P+0+1/2x 2p v22
v22=2gh
v2=?(2gh)
(v2/v1)^2=2:1

Answered by  | 16th Nov, 2012, 05:53: PM

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