Energy nth orbit, -k/(n)2 ;k:constnt, then as n increases how can the | energy | increase?

Asked by anuragchakraborty | 28th Feb, 2010, 10:07: PM

Expert Answer:

The enrgy of the n = (infinity) level is the highest since it has the highest potential energy. 

This is taken as E  = 0

As we come closer towards the nucleus, the enrgy decreases and hence becomes negative.

The negative sign is of significance here.


Energy nth orbit, -k/(n)2 ;k:constnt, t

Since as n increases the deniminatotr will increase. So, the fraction will decraese.

But since the negative sign is there, it menas that E is increasing

For example: -3< -2

Answered by  | 2nd Mar, 2010, 10:13: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.