CBSE Class 10 Answered
electricity
Asked by | 08 Dec, 2008, 12:06: PM
The resistance of a wire R = ρ l/A
where ρ - resistivity of the wire(its constant for a material)
l - Length of the wire
A - area of the crossection
Now A = πr2 where r - radius of the cross section. If d is the diameter then
r = d/2
Hence A = 1/4πd2
This implies R 1/A
R
1/d2
i.e. if the diameter is doubled the resistance reduces to 1/4 of the original value.
Answered by | 08 Dec, 2008, 01:51: PM
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