Asked by yashpinto | 18th May, 2010, 11:42: PM

Expert Answer:

Dear student,

As the resistors are in parallel,

I = I1+I2+I3

Resistors 1 and 2 are always connected, only the last resistor R3 is connected through a switch.

WHen, key is open, I = 0.6 Meas I1 = 0.6/2 = 0.3A, I2 = 0.6/2 = 0.3A

Now. when the key is closed, as the resistors are identical R3 = 0.3A, Hence total current flowing will be 0.3+0.3+0.3

 = 0.9 A

Hope this helps.



Answered by  | 19th May, 2010, 08:07: AM

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