electricity

Asked by yashpinto | 18th May, 2010, 11:42: PM

Expert Answer:

Dear student,

As the resistors are in parallel,

I = I1+I2+I3

Resistors 1 and 2 are always connected, only the last resistor R3 is connected through a switch.

WHen, key is open, I = 0.6 Meas I1 = 0.6/2 = 0.3A, I2 = 0.6/2 = 0.3A

Now. when the key is closed, as the resistors are identical R3 = 0.3A, Hence total current flowing will be 0.3+0.3+0.3

 = 0.9 A

Hope this helps.

Team

Topperlearning.com

Answered by  | 19th May, 2010, 08:07: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.