Electricity question

Asked by ravikiran | 9th Jan, 2010, 01:07: PM

Expert Answer:

H2SO4 2H+ + SO42-

H2O H+ + OH-

At cathode:

H++ e- H

H + H H2

At anode:

OH- OH + e-

4OH 2 H2O + O2

The sulphate ions remain unchanged.

Q = 2 F

At anode,

2F of electricity will release 32 g of oxygen gas

1Fof electricity will release 16 g of oxygen gas

 

At cathode,

2 F of electricity will release 2 g of hydrogen gas

1F of electricity will release 1g of hydrogen gas

Answered by  | 11th Jan, 2010, 09:45: AM

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