Electricity question
Asked by ravikiran
| 9th Jan, 2010,
01:07: PM
Expert Answer:
H2SO4 2H+ + SO42-
H2O H+ + OH-
At cathode:
H++ e- H
H + H H2
At anode:
OH- OH + e-
4OH 2 H2O + O2
The sulphate ions remain unchanged.
Q = 2 F
At anode,
2F of electricity will release 32 g of oxygen gas
1Fof electricity will release 16 g of oxygen gas
At cathode,
2 F of electricity will release 2 g of hydrogen gas
1F of electricity will release 1g of hydrogen gas
Answered by
| 11th Jan, 2010,
09:45: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change