Asked by  | 8th Dec, 2008, 09:46: PM

Expert Answer:

In the first case:

Voltage drop= V

Current= I/10

Power dissipated=VI/10

In second case ,

Voltage drop=V/10


Power dissipated=VI/10

Hence voltage drawn by individual bulbs is more in first case,current drawn is more in second case and bulbs are equally brighter.

Answered by  | 10th Dec, 2008, 10:56: PM

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