Easy way to memorise the formulaes and conversions.
Asked by Palak Diwan
| 21st Dec, 2013,
11:41: AM
Expert Answer:
The above figure is the figure described in question no.4 of 13.1 of NCERT X
As you can see from the figure, the base of the hemispehrical part is a circle.
When the hemispherical part is surmounting the cubical part, the circulart part will get hided in the cubical part. Therfore, we are subtracting the area of the circulart part from the total surface area.
Similarly, the following figure describes the problem of question no.5 of 13.1 of NCERT X.
When a hemispherical part cut out from one face of the cubical part, the circulart part will get hided in the cubical part. Therfore, we are subtracting the area of the circulart part from the total surface area.
There is no short cut to memorize formulae. Please read and write the formulae again and again.
Answered by Vimala Ramamurthy
| 22nd Dec, 2013,
03:38: PM
The above figure is the figure described in question no.4 of 13.1 of NCERT X
As you can see from the figure, the base of the hemispehrical part is a circle.
When the hemispherical part is surmounting the cubical part, the circulart part will get hided in the cubical part. Therfore, we are subtracting the area of the circulart part from the total surface area.
Similarly, the following figure describes the problem of question no.5 of 13.1 of NCERT X.
When a hemispherical part cut out from one face of the cubical part, the circulart part will get hided in the cubical part. Therfore, we are subtracting the area of the circulart part from the total surface area.
There is no short cut to memorize formulae. Please read and write the formulae again and again.
Answered by Vimala Ramamurthy
| 22nd Dec, 2013,
03:38: PM
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