∫ dx / (x [6(logx)^2+7logx+2] )

Asked by sunil2791 | 3rd Oct, 2017, 07:21: PM

Expert Answer:

begin mathsize 16px style integral fraction numerator dx over denominator straight x open square brackets 6 open parentheses logx close parentheses squared space plus space 7 logx space plus space 2 close square brackets end fraction
Put space log space straight x space equals space straight t
rightwards double arrow 1 over straight x dx space equals space dt
integral fraction numerator dx over denominator 6 straight t squared space plus space 7 straight t space plus space 2 end fraction
1 over 6 integral fraction numerator dx over denominator straight t squared space plus space begin display style fraction numerator 7 straight t over denominator 6 end fraction end style space plus space begin display style 2 over 6 end style end fraction
Now space use space completing space square space method space to space solve space further. end style

Answered by Sneha shidid | 28th Dec, 2017, 10:15: AM

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