drop of water from the roof of a house 6m high fall at regular intervals.the first drop reaches the groun at an instant of time when third drop leaves the roof. find the height of second drop at that instant?
Asked by Sindhura K Reddy | 16th Aug, 2010, 09:04: PM
The interval between first and thrid drop is, is the time taken by the first drop to fall through 6m,
t = √(2H/g) = √(2x6/9.8) = 1.11 sec.
Hence the interval is, 1.11/2 = 0.56 sec.
Hence second drop will for 0.56 sec, it's height,
= (1/2)x9.8x0.562 = 1.51 m from roof or 6 - 1.51 = 4.49 m from ground.
Answered by | 16th Aug, 2010, 09:19: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number