draw the graph of the following system of linear equation :

Asked by  | 23rd May, 2013, 11:12: AM

Expert Answer:

x+3y=6 (1)
2x-3y=12 (2)
 
For the first equation, draw a straight line passing through (6,0) and (0,2). This line has a negative slope. 
 
For the second equation, draw a straight line passing through (6,0) and (0,-4). This line has a positive slope. 
 
Furthermore, the 2 lines intersect at (6,0) and the area bound by the 2 lines and y axis is a triangle with vertices, A(0,-4) B(0,2) and C(6,0). 
 
Area of the triangle = 1/2 * b*h 
Here base = AB = 6 units
height = OC =6 unis
Hence, area of triangle = 1/2*6*6 = 18 sq units. 
 

Answered by  | 24th May, 2013, 01:55: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.