Draw a triangle ABC of any measure and then construct a perpendicular from A on BC.
Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM
1. Draw a triangle ABC of any measure.
2. Taking A as a centre and a suitable radius, draw an arc which cut the line BC at two points P and Q.
3. Taking P and Q as centre and suitable radius draw two arcs and let them intersect at R.
4. Join AR.
5. Hence, AR is the required perpendicular from A on BC.
Answered by | 4th Jun, 2014, 03:23: PM
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