Draw a kite EFGH such that EF=5cm, and HE=3cm, andF= 40°. Write the steps of construction.
Asked by Topperlearning User | 5th Feb, 2014, 11:15: AM
EFGH is a kite, so we have GF=EF=5cm and HG=HE=3cm.
Steps of Construction:
a)Draw EF =5cm.
b)At F, Draw angle XFE=40°.
c)With F as centre and radius equal to5cm, draw an arc to intersect FX at point G.
d)With G as centre and radius 3cm draw an arc.
e)With E as center and radius 3cm, draw another arc which meets the arc of step(d) at point H.
f)Join HE and HG.
EFGH is the required kite.
Answered by | 5th Feb, 2014, 01:15: PM
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