DOUBT: NCERT Exercise Q.no.15

Asked by janasati | 25th Jan, 2011, 01:37: AM

Expert Answer:

ΔH = 715+(2x242)-30.5-(135.5)
ΔH =1304 kjmol-1
bond enthalpy =1304/4 =326 kjmol-1

Answered by  | 25th Jan, 2011, 09:28: AM

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