DOUBT: NCERT Exercise Q.no.15
Asked by janasati | 25th Jan, 2011, 01:37: AM
Expert Answer:
ΔH = 715+(2x242)-30.5-(135.5)
ΔH =1304 kjmol-1
bond enthalpy =1304/4 =326 kjmol-1
Answered by | 25th Jan, 2011, 09:28: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change