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CBSE Class 11-science Answered

DOUBT: NCERT Exercise Q.no.15
Asked by janasati | 25 Jan, 2011, 01:37: AM
Expert Answer
ΔH = 715+(2x242)-30.5-(135.5)
ΔH =1304 kjmol-1
bond enthalpy =1304/4 =326 kjmol-1
Answered by | 25 Jan, 2011, 09:28: AM
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