divide 24 in two parts such that they are in AP and their product is 440

Asked by  | 13th Nov, 2012, 12:04: AM

Expert Answer:

Please check, the question should be to divide 24 into three parts. The solution is as follows:
 

The parts are in AP, so let the parts be a-d, a and a+d

where the first term =a-d

the common difference =d

Given, sum =24cm

a-d + a+a + d = 24cm

3a = 24cm

a =8cm

Given: Product of the terms = 440

(a-d) (a) (a+d) = 440

(8-d) (8+d) (8) =440

(8-d)(8+d) = 55

82 -d2 = 55

64 - d2 = 55

d2 = 64-55

d2 = 9

d = +3, -3

When d = 3,

AP- a-d , a, a+d

so the AP is 8-3, 8, 8+3

AP = 5, 8, 11

When d = -3, AP = 11, 8, 5
 
So, the three parts are 5, 8, 11.

Answered by  | 13th Nov, 2012, 10:20: PM

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