divide 24 in three parts such that they are in AP and their product is 440

Asked by Yashodhan Bhuskute | 25th Oct, 2012, 04:38: PM

Expert Answer:

The parts are in AP, let the terms be a-d, a and a+d

where the first term =a-d

the common difference =d

Given, sum =24cm

a-d + a+a +d = 24cm

3a = 24cm

a =8cm

Given: Product of the terms = 440

(a-d) (a) (a+d) = 440

(8-d) (8+d) (8) =440

(8-d)(8+d) = 55

82 -d2 = 55

64 - d2 = 55

d2 = 64-55

d2 = 9

d = 3 or -3

AP- a-d , a, a+d

so the AP is 8-3, 8, 8+3 or 8+3,8,8-3

AP = 5, 8, 11 or 11, 8, 5

Answered by  | 25th Oct, 2012, 05:07: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.