divide 24 in three parts such that they are in AP and their product is 440
Asked by Yashodhan Bhuskute | 25th Oct, 2012, 04:38: PM
Expert Answer:
The parts are in AP, let the terms be a-d, a and a+d
where the first term =a-d
the common difference =d
Given, sum =24cm
a-d + a+a +d = 24cm
3a = 24cm
a =8cm
Given: Product of the terms = 440
(a-d) (a) (a+d) = 440
(8-d) (8+d) (8) =440
(8-d)(8+d) = 55
82 -d2 = 55
64 - d2 = 55
d2 = 64-55
d2 = 9
d = 3 or -3
AP- a-d , a, a+d
so the AP is 8-3, 8, 8+3 or 8+3,8,8-3
AP = 5, 8, 11 or 11, 8, 5
The parts are in AP, let the terms be a-d, a and a+d
where the first term =a-d
the common difference =d
Given, sum =24cm
a-d + a+a +d = 24cm
3a = 24cm
a =8cm
Given: Product of the terms = 440
(a-d) (a) (a+d) = 440
(8-d) (8+d) (8) =440
(8-d)(8+d) = 55
82 -d2 = 55
64 - d2 = 55
d2 = 64-55
d2 = 9
d = 3 or -3
AP- a-d , a, a+d
so the AP is 8-3, 8, 8+3 or 8+3,8,8-3
AP = 5, 8, 11 or 11, 8, 5
Answered by | 25th Oct, 2012, 05:07: PM
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