CBSE Class 10 Answered
distance formula
Asked by rohit1993 | 05 Jul, 2008, 10:16: AM
Expert Answer
PA = PG+GA and PB=PG+GB and PC=PG+GC
So PA2+PB2+PC2 = PG2+GA2+2PG.GA+ PG2+GB2+2PG.GB+ PG2+GC2+2PG.GC
=3PG2+GA2+GB2 +GC2 +2PG.(GA+GB+GC)
since (GA+GB+GC) = 0
so we are left with 3PG2+GA2+GB2 +GC2 which is equal to R.H.S.
Answered by | 12 Sep, 2008, 04:10: AM
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