distance formula

Asked by rohit1993 | 5th Jul, 2008, 10:16: AM

Expert Answer:

PA = PG+GA  and PB=PG+GB and PC=PG+GC

So PA2+PB2+PC2 = PG2+GA2+2PG.GA+ PG2+GB2+2PG.GB+ PG2+GC2+2PG.GC

=3PG2+GA2+GB2 +GC2 +2PG.(GA+GB+GC)

since (GA+GB+GC) = 0

so we are left with 3PG2+GA2+GB2 +GC2 which is equal to R.H.S.

Answered by  | 12th Sep, 2008, 04:10: AM

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