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CBSE Class 11-science Answered

DIMENSIONAL ANALYSIS
Asked by | 29 Jun, 2008, 10:54: AM
answered-by-expert Expert Answer

use the formula n1u1 = n2u2

and equate both the sides.

regards

toppers expert

Answered by | 29 Jun, 2008, 11:12: PM
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CBSE 11-science - Physics
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Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
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CBSE 11-science - Physics
.A SHM is expressed by the equation x = A cos (ωt + φ) and the phase angle φ =0. Draw graphs to show variation of displacement, velocity and acceleration for one complete curve in SHM.
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
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CBSE 11-science - Physics
the dimension of stopping potential vo in photoelectric effect in units of plank's constant 'h',speed of light 'c' and gravitational constant 'G' and ampereA
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
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CBSE 11-science - Physics
In this que while solving it we take D F of alpha =D.F of beta.Why is it so?
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Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
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CBSE 11-science - Physics
In physics if 2 quantities are dimensionless then their dimensional formula are equal?
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
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CBSE 11-science - Physics
7. State the relation between maximum range and maximum height of the projectile if the angle of projection is 45 deg
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
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CBSE 11-science - Physics
The second overtone of a pipe closed at one end has the same frequency as the third overtone of a pipe open at both ends. Compare the length of the pipes
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
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CBSE 11-science - Physics
two forces whose magnitude are in the 3:5 give a resultant f Jatio 3:5 give 20 N. If fac 20. It fue angle of thread indination of each face find Magnitude
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Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
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CBSE 11-science - Physics
Q17. The velocity time relation of an electron starting from rest is given by v = kt where k = 6m / (s ^ 2) Calculate the distance traversed in 2 sec. 122
Asked by om636694 | 04 Mar, 2024, 09:10: PM
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CBSE 11-science - Physics
pressure of a gas in a closed cylinder is expressed in the following manner p=pa+hpg identity the expression for absolute pressure and gauge pressure
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
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