CBSE Class 12-science Answered
Diffrentiation
Asked by Rahulsinha1993 | 25 Apr, 2010, 09:10: AM
y = (1+tanx) /
(1-tan x)
tan 45 = 1,
Hence, we can write,
y = (tan 45 + tanx) /
(1 - tan x tan 45)
= (tan (45+x))
dy/dx = [1/2(tan (45+x))] sec2(45+x)
= [1/2(tan (45+x))] [1 + tan2(45+x)]
Regards,
Team,
TopperLearning.
Answered by | 25 Apr, 2010, 01:13: PM
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