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CBSE Class 12-science Answered

Diffrentiation
Asked by Rahulsinha1993 | 25 Apr, 2010, 09:10: AM
Expert Answer

y = (1+tanx) / (1-tan x)

tan 45 = 1,

Hence, we can write,

y = (tan 45 + tanx) / (1 - tan x tan 45)

= (tan (45+x))

dy/dx = [1/2(tan (45+x))] sec2(45+x)

= [1/2(tan (45+x))] [1 + tan2(45+x)]

Regards,

Team,

TopperLearning.

 

Answered by | 25 Apr, 2010, 01:13: PM
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