CBSE Class 9 Answered
difficult sum
Asked by | 21 Oct, 2008, 06:02: PM
Expert Answer
I think , you mean
a cylinder and a cone have equal radii of their bases and equal heights. if their curved surface areas are in the ratio 8:5 then show that the ratio of the radius of each to the height of each as 3:4
2 pi r h / pi r l = 8/ 5
i.e 2h /l = 8/5
i.e h / sq root ( h 2 + r 2) = 4/5
Squaring and cross multiplying , we get
25h2 = 16 ( h 2 + r 2)
(25 - 16 ) h2 = 16 r 2
9h2 = 16 r 2
r 2 / h 2 = 3 9/16
r/ h = 3/4
Answered by | 21 Oct, 2008, 06:41: PM
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