Asked by  | 12th Mar, 2008, 11:44: PM

Expert Answer:

Let logx= u. this implies du/dx= 1/x

so y= logu

this implies dy/du= 1/u

therefore, dy/dx= dy/du * du/dx

                           =1/ ux

                          = 1/xlogx

therefore, 2nd derivative is equal to = -(1+logx)/ (xlog)square

(by using division formua)

Answered by  | 17th Mar, 2008, 05:34: PM

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