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Differentiate: e to the power x3 + 1/2 logx

Asked by TEJAS SATISHKUMAR RANINGA | 29th Sep, 2010, 12:00: AM

Expert Answer:

$y = e^{x^{3}} + \frac{1}{2} logx$ $\frac{dy}{dx} = e^{x^{3}} \frac{d (x^{3})}{dx} + \frac{1}{2} \frac{1}{x} = e^{x^{3}} (3 x^{2}) + \frac{1}{2 x} = 3 x^{2} e^{x^{3}} + \frac{1}{2 x}$ ">

Answered by | 29th Sep, 2010, 09:34: PM

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