differentiate 10^x
Asked by rashmi rashmi | 15th Aug, 2012, 09:29: PM
Expert Answer:
y=10^x
Take log on both sides, we get,
logy=x*log10
Differentiating w.r.t x, we get
1/y dy/dx=log10
dy/dx=ylog10
dy/dx=10^xlog10 [as y=10^x]
logy=x*log10
1/y dy/dx=log10
dy/dx=ylog10
dy/dx=10^xlog10 [as y=10^x]
Answered by | 15th Aug, 2012, 10:21: PM
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