differentiate 10^x
Asked by rashmi rashmi
| 15th Aug, 2012,
09:29: PM
Expert Answer:
y=10^x
Take log on both sides, we get,
logy=x*log10
Differentiating w.r.t x, we get
1/y dy/dx=log10
dy/dx=ylog10
dy/dx=10^xlog10 [as y=10^x]
logy=x*log10
1/y dy/dx=log10
dy/dx=ylog10
dy/dx=10^xlog10 [as y=10^x]
Answered by
| 15th Aug, 2012,
10:21: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change