CBSE Class 9 Answered
Diagonals AC , BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) =ar (BOC).
Asked by | 13 Sep, 2008, 04:12: PM
Expert Answer
Denote
the Area (triangle AOD) as Area(I)
The Area (triangle BOC ) as Area(II)
Area (triangle AOB) as Area(III)
Given that
Area(I)=Area(II)
So,
Area(I)+Area(III)=Area(II)+Area(III)
This gives us that,
Area(triangle ADB)=Area(triangle ACB)
So, AB must be parallel to DC ..(as triangles on the same base and equal in area must lie between same parallels)
So, ABCD is a trapezium as one pair of opposite sides is parallel.
Answered by | 22 Jan, 2009, 01:45: PM
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