determine the ratio in which the line 3x+y-9=0 divides the segment joining the points (1,3) and (2,7).

Asked by  | 15th Feb, 2012, 03:13: PM

Expert Answer:

Let the point be (x,y) , and the ratio it divides (1,3) and (2,7) be k:1
By section formula , x = (2k+1)/(k+1)  ,  y = (7k+3)/(k+1)
his point also lies on the given line so it would satisfy the equation 3x+y-9=0
3(2k+1) + (7k+3) -9(k+1) = 0
k = 3/4
ratio = 3:4

Answered by  | 15th Feb, 2012, 07:12: PM

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