determine the point on the graph of the linear equation 4x-5y=7,whose- a.abscissa is 3 times its ordinate b.ordinate is 2 times the abscissa

Asked by anusarika mohanty | 23rd Dec, 2013, 05:57: PM

Expert Answer:

The given equation is 4x-5y=7.
(a) Abscissa is 3 times ordinate
Let the required point be (3p, p).
So, we have:
4(3p)-5(p)=7
12p-5p=7
7p=7
p=1
Thus, the point is (3, 1)
 
(b) Ordinate is 2 times abscissa.
Let the required point be (p, 2p).
So, we have:
4(p)-5(2p)=7
4p-10p=7
-6p=7
p=-7/6
Thus, the point is (-7/6, -7/3).

Answered by  | 23rd Dec, 2013, 06:05: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.