Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10-2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.

(R = 0.0821 L atm K-1 mol-1, Molar mass of K2SO4 = 174 g mol-1)

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

w2 = 2.5 × 10-2 g (Mass of K2SO4) and M2 = 174 g mol-1 (Molar mass of K2SO4)

V = 2L, R = 0.0821 L atm K-1 mol-1 and T = 25°C = 298 K

Osmotic pressure ,

Answered by  | 4th Jun, 2014, 03:23: PM