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CBSE Class 12-science Answered

Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10-2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated. (R = 0.0821 L atm K-1 mol-1, Molar mass of K2SO4 = 174 g mol-1)
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

w2 = 2.5 × 10-2 g (Mass of K2SO4) and M2 = 174 g mol-1 (Molar mass of K2SO4)

V = 2L, R = 0.0821 L atm K-1 mol-1 and T = 25°C = 298 K

Osmotic pressure ,

Answered by | 04 Jun, 2014, 03:23: PM
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