determine the osmotic pressure of 1g of pottasium sulphate in 2l of water at 25 degree celsius assuming tat it is completelf dissociated
Asked by Akshaya Parthasarathy | 10th Jul, 2011, 12:00: AM
Expert Answer:
Since K2SO4 is completely dissociated, so i =3
K2SO4 
2K+ + SO4 2-
= i WB X RT / MB X V
= 3 X 1 X 0.082 X 298 /( 174 X 2)
= 0.211 atm
K2SO4 2K+ + SO4 2-
= i WB X RT / MB X V
= 3 X 1 X 0.082 X 298 /( 174 X 2)
= 0.211 atm
Answered by | 11th Jul, 2011, 10:23: AM
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