determine the osmotic pressure of 1g of pottasium sulphate in 2l of water at 25 degree celsius assuming tat it is completelf dissociated

Asked by Akshaya Parthasarathy | 10th Jul, 2011, 12:00: AM

Expert Answer:

Since  K2SO4 is completely dissociated, so i =3

    K2SO 2K+  +  SO4 2-

 = i WB X RT / MB X V

= 3 X 1 X 0.082 X 298 /( 174 X 2)

= 0.211 atm


Answered by  | 11th Jul, 2011, 10:23: AM

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