Determine the number of bromide ion in 0.2 mole of Mg Br2.

Asked by Amyra B | 8th Dec, 2013, 02:02: PM

Expert Answer:

Solution:

Mass of 1 mole of magnesium bromide (MgBr2) = 24 + 2 × 80 = 24 + 160 = 184 g

So 184 g MgBr2 = 1 mole

But 1 molecule of MgBr2 contains 2 bromide ions.

Br- ions present= 2 × 6 × 1023 bromide ions.

If 1 mole of MgBr2 contains = 12 × 1023 bromide ions.

0.2 mole of MgBr2 contains = 2.4 × 1023 bromide ions

Answered by Vaibhav Chavan | 9th Dec, 2013, 12:33: PM

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