Determine the emf of the galvanic cell below

Asked by Ujjwal Kumar | 22nd Sep, 2010, 07:26: PM

Expert Answer:

By Using the formula: 
cell= Eo - (.0592/n)log10 (1/Mn+)
Ag-------------->Ag+ 
Here, n=1
E cell=Eo - (.0592/1) log10 (1/Ag+) 
=.80-log10(1/.1)
Ecell= -.20V

Answered by  | 22nd Sep, 2010, 08:03: PM

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