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CBSE Class 12-science Answered

Determine the emf of the galvanic cell below
Asked by Ujjwal Kumar | 22 Sep, 2010, 07:26: PM
answered-by-expert Expert Answer
By Using the formula: 
cell= Eo - (.0592/n)log10 (1/Mn+)
Ag-------------->Ag+ 
Here, n=1
E cell=Eo - (.0592/1) log10 (1/Ag+) 
=.80-log10(1/.1)
Ecell= -.20V
Answered by | 22 Sep, 2010, 08:03: PM
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