Determine the emf of the galvanic cell below
Asked by Ujjwal Kumar
| 22nd Sep, 2010,
07:26: PM
Expert Answer:
By Using the formula:
E cell= Eo - (.0592/n)log10 (1/Mn+)
Ag-------------->Ag+
Here, n=1
E cell=Eo - (.0592/1) log10 (1/Ag+)
=.80-log10(1/.1)
Ecell= -.20V
Here, n=1
Answered by
| 22nd Sep, 2010,
08:03: PM
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