Determine the emf of the galvanic cell below

Asked by Ujjwal Kumar | 22nd Sep, 2010, 07:26: PM

Expert Answer:

By Using the formula: 
E cell= Eo - (.0592/n)log10 (1/Mn+)
Ag-------------->Ag+ 
Here, n=1
E cell=Eo - (.0592/1) log10 (1/Ag+) 
=.80-log10(1/.1)
Ecell= -.20V

Answered by  | 22nd Sep, 2010, 08:03: PM

Ask Doubt

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.