Detailed solution please.

Asked by g_archanasharma | 8th Feb, 2019, 05:49: PM

Expert Answer:

let  the bond  dissociation energy of,
X2=  x kJ/mol
XY=x kJ/mol
Y2=0.5x kJ/mol
 
We have,
 
1/2 X + 1/2Y → XY      ΔH = -200   kJ/mol
We  know  that,
 
ΔHreaction  = (bond dissociation energy of reactants) - ( bond  dissociation energy of products)
 
                    = x over 2 plus fraction numerator 0 times 5 x over denominator 2 end fraction minus x equals negative 200

fraction numerator 1.5 straight x over denominator 2 end fraction minus x equals space minus space 200

fraction numerator 0.5 x over denominator 2 end fraction space equals space 200


0.25 x space equals space 200 space space

straight x space space equals space 800 space kJ divided by mol
Bond  dissociation energy of X is  800 kJ/mol.
 

Answered by Varsha | 11th Feb, 2019, 12:11: AM

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