Derive the relation between electric intensity and electric potential .. and explain in detail

Asked by gopalkil | 21st Sep, 2010, 07:44: PM

Expert Answer:

The relation is very simple. Electric field intensity is equal to the negative of rate of change of potential with respet to the distance or it can be defined as the negative of the rate of derivative of potential difference, V with respect to r, E = - dV/dr.

Answered by  | 21st Sep, 2010, 07:50: PM

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