CBSE Class 12-science Answered
Derive an expression for Electric intensity at a point near a charged conductor.
Asked by | 30 Jan, 2010, 10:04: PM
Expert Answer
The charged conductor can be a rod, infinite sheet, or a sphere.
We consider a charged rod.
Draw a Gaussian surface around the charged rod, of radius R, at a radial distance r>R.
The Gaussian surface is imaginary cylinder with radius r, and length L.
The charge inclosed by the Gaussian surface λL, where λ is uniform linear charge density.
E.dA = λL/ε0
E(2πrL) = λL/ε0
E = λ/(2πrε0)
Regards,
Team,
TopperLearning.
Answered by | 02 Feb, 2010, 10:23: AM
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