Derive an expression for Electric intensity at a point near a charged conductor.

Asked by  | 30th Jan, 2010, 10:04: PM

Expert Answer:

The charged conductor can be a rod, infinite sheet, or a sphere.

We consider a charged rod.

Draw a Gaussian surface around the charged rod, of radius R, at a radial distance r>R.

The Gaussian surface is imaginary cylinder with radius r, and length L.

The charge inclosed by the Gaussian surface λL, where λ is uniform linear charge density.

E.dA = λL/ε0

E(2πrL) = λL/ε0

E = λ/(2πrε0)

Regards,

Team,

TopperLearning.

Answered by  | 2nd Feb, 2010, 10:23: AM

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