Derivatives of Inverse Trignometric Functions..

Asked by  | 4th Jul, 2009, 12:43: PM

Expert Answer:

if suppose you have to find te derivative of sin inverse of x.

 then assume sin inverse of x= y

then

x=siny

dx/dy=cosy

 

then dy/dx

=1/[dx/dy]

=1/cosy

then put y interms of x , you will have the answer.

remember that x lies bet -1 and +1

so,

 y lies bet

-pie by 2 and +pie by2

then you can put the value of cosp in terms of x.

Answered by  | 4th Jul, 2009, 06:26: PM

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