Derivatives of Inverse Trignometric Functions..

if suppose you have to find te derivative of sin inverse of x.

 then assume sin inverse of x= y

then

x=siny

dx/dy=cosy

 

then dy/dx

=1/[dx/dy]

=1/cosy

then put y interms of x , you will have the answer.

remember that x lies bet -1 and +1

so,

 y lies bet

-pie by 2 and +pie by2

then you can put the value of cosp in terms of x.