de broglie
Asked by | 13th Mar, 2010, 01:52: PM
Expert Answer:
(c) 
(3/8)
de Broglie wavelength, λ = h/(2πmkT)
where h - Planck's constant, m - mass of atom, k - Boltzmann constant, T - temperature in K.
Hydrogen molecules, H2, will have 2 protons,
Helium molecules will have 2 protons and 2 neutrons. Masses of protons and neutrons are approximately same. Hence Helium gas molecule will be TWICE massive than hydrogen molecule.
λHydrogen/λHelium = [(mT)Hydrogen/(mT)Helium] = (300/(2x400)) = (3/8)
Regards,
Team,
TopperLearning.
Answered by | 13th Mar, 2010, 02:48: PM
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