D,E,F are midpoints of BC,CA,,AB of triangle ABC.Show that BDEF is a parallelogram.
Asked by | 29th Oct, 2009, 08:58: PM
Since D and E are the mid points of the side of the triangle BC and CA.
By converse of Basic Proportionality Theorem,
DE || AB.
Similarly FE II BC and DF || AC.
⇒ BDEF is a parallelogram.
Answered by | 4th Nov, 2009, 03:59: PM
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