CBSE Class 10 Answered
cyclic quadrilateral
Asked by fathima12 | 10 Jun, 2010, 12:57: PM
Expert Answer
Dear Student
Following is the solution of your question
PQRS is acyclic quadrilateral sum of its opposite angles is 180o
PQRS is acyclic quadrilateral sum of its opposite angles is 180o
Angle P must be 4b+20
So ‹P +‹R = 4b + 20-4b=180 i.e b-a = 40
So ‹P +‹R = 4b + 20-4b=180 i.e b-a = 40
‹Q + ‹ S = 3b -5 -7a + 5=180
3b-7a = 180
Solving we get a = 15
b= 25
Solving we get a = 15
b= 25
Angles will be
4b + 20 = 4(25) + 20 = 120°
3b– 5 = 3(25) – 5 = 70°
–4a = –4(–15) = 60°
–7a + 5 = –7(–15) + 5 = 110°
Regards
Team Topperlearning
Answered by | 14 Jul, 2010, 02:34: PM
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