coordinates of moving particle at any time t are given by:x=ctsq. and y=btsq. ,what is speed of particle at time t?

Asked by akkisara | 11th Jun, 2011, 09:54: PM

Expert Answer:

For find the speed of the particle:
Vx = dx/dt = d(ct2)/dt = 2c t
and Vy = dy/dt = d(bt2)/dt = 2b t
speed = sqrt (V2x + V2y) = sqrt (4c2t2 + 4b2t2) = 2 t sqrt (c2 + b2)

Answered by  | 13th Jun, 2011, 01:59: PM

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