coordinate geometry

Asked by  | 27th Jan, 2009, 07:56: PM

Expert Answer:

Remember that the diagonals of a parallelogram bisect each other.

So, the mid points of both of them are the same .

So here, we will find the mid point of  one diagonal and assume it to be themid point of the other diagonal, too.

Ler A(3,-4)

C((6,-2)

B(-1,-3)

D(x,y)

Mid point of AC, say P, using mid point formulais(3+6/2,-4-2/2)

So P has coordinates(9/2,-3)

This must be the mid point for BD  as well.

so(-1+x/2 ,-3+y/2)=(9/2,-3)

equate the x and y coordinates , which will give you the answer.

Answered by  | 28th Jan, 2009, 09:27: AM

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