Coordinate geometry

Asked by sonali221994 | 15th Dec, 2009, 04:56: PM

Expert Answer:

If equation of the circle

(x-(3p+1))2 + (y-(2p-1))2 = 102 

Since the circle passes through (-1,-3)

(-1-(3p+1))2 + (-3-(2p-1))2 = 102 

(-3p-2)2 + (-2p-2)2 = 100 

13p2 + 20p + 8 = 100

13p2 + 20p - 92 = 0

p = {-20±(400+4x13x92)1/2}/26 = {-20±72}/26 

Hence p = -92/26 = -46/13 or 52/26 = 2.

Regards,

Team,

TopperLearning. 

Answered by  | 15th Dec, 2009, 05:42: PM

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