Coordinate Geometry

Asked by  | 10th Oct, 2008, 12:55: PM

Expert Answer:

 

 

B is at the oriigin , so B(0,0) ,

BC lies on the x axis and BC = a , so C(a, 0)

Let A (x,y)

So AB 2 = x 2+ y2 = a 2  so y2 = a 2  - x2

AC2 = (x -a ) 2 + y 2   =  a 2

Substituting, y2 = a 2  - x2

 (x -a ) 2 + a 2  - x2   =  a 2

So a2 - 2ax = 0

a2  =  2ax

x = a/ 2, A(a/2  ,  a /2)

 

 

 

Answered by  | 10th Oct, 2008, 05:54: PM

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