CBSE Class 10 Answered
coordinate geometry
Asked by | 26 Sep, 2008, 05:52: PM
Expert Answer
If the area of quadrilateral is zero
So the area of the sum of the two triangles formed by joining the vertices (1,2) and (7 , -4)
1/2 [ 1(6+4)-5 (-4-2) + 7 (2 -6) + 7(-2-2) + k (2 +4) +1 ( -4 + 2)] = 0
1/2 [ 10 + 80 - 28 -28 + 6k -2 ] = 0
-18 + 6k = 0
k = 3
Answered by | 26 Sep, 2008, 06:50: PM
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