COORDINATE GEOMETRY
Asked by
| 10th Jan, 2009,
08:53: PM
let the point is (h,k) so { slope of line joining (h,k) and (-5,1) } * { slope of line joining (h,k) and (3,2) } = -1
slope of line joining (h,k) and (-5,1) = (k-1) / (h+5)
slope of line joining (h,k) and (3,2) = (k-2) / (h-3)
so (k-1) (k-2) / (h+5) (h-3) = -1 by solving we get locus is a circle x2 + y2+2x - 3y - 13= 0
Answered by
| 10th Jan, 2009,
10:58: PM
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