COORDINATE GEOMETRY

Asked by  | 10th Jan, 2009, 08:53: PM

Expert Answer:

let the point is (h,k)   so   { slope of line joining (h,k) and (-5,1) } * { slope of line joining (h,k) and (3,2) }  = -1

slope of line joining (h,k) and (-5,1) = (k-1) / (h+5)

slope of line joining (h,k) and (3,2)  =  (k-2) / (h-3)

so  (k-1) (k-2) / (h+5) (h-3)  = -1  by solving we get locus is a circle x2 + y2+2x - 3y - 13= 0

Answered by  | 10th Jan, 2009, 10:58: PM

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