Asked by sonali221994 | 15th Dec, 2009, 04:52: PM
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2/ A(0,0) and B(3,0), hence the length of the side of equilateral triangle, 3 units.
Let C(x,y) be the third vertex.
Length of the side, AC = (x2 + y2)1/2 = 3 i.e. x2 + y2 = 9.......(1)
and for side BC = (x - 3)2 + y2 = 9 i.e. x2 - 6x +9 + y2 = 9 .......(2)
Subtracting (2) from (1),
gives, x = 3/2,
and hence y = 33/2
Answered by | 15th Dec, 2009, 05:53: PM
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