CONTINUITY

Asked by  | 15th Sep, 2008, 08:00: PM

Expert Answer:

here if we apply L.Hospital rule then

lim x->1 (x²+3x+p) / 2(x²-1) = lim x->1 (2x+3) / 2(2x)= 5/4

so no matter what is the value of p, f(x) is continuous at x=1

so p can take any value.

Answered by  | 17th Sep, 2008, 06:32: PM

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