continued q. 7

Asked by nilesh.dhote74 | 15th May, 2020, 09:18: PM

Expert Answer:

 Question - 

A 4 m long rod of negligible weight is to be balanced about a point 125 cm from one end and A load of 18 kgf is suspended at a point 60 cm from the support on the shorter arm.

(a) If a weight W is placed at a distance of 250 cm from the support on the longer arm, Find W.
(b) If a weight 5 kgf is kept to balance the rod, find its position.
(c) To which class of lever does it belong?

Solution - 

Total length of rod = 4 m = 400 cm

(a)18kgf load is placed at 60 cm from the support.

W kgf weight is placed at 250 cm from the support.

By the principle of moments

18 x 60 = W x 250

W = 4.32 kgf

 

(b)Given W=5 kgf

18kgf load is placed at 60 cm from the support.

Let 5 kgf of weight is placed at d cm from the support.

By the principle of moments

18 x 60 = 5 x d

d = 216 cm from the support on the longer arm

 

(c)It belongs to class I lever.

Answered by Shiwani Sawant | 16th May, 2020, 12:08: AM