CBSE Class 8 Answered
Let the required ||gm be EFGH with EF = 5.2cm and FG =4.7cm and EG = 7.6cm.
Steps of Construction:
a)Draw EF = 5.2cm.
b)With E is centre and radius 7.6cm, draw an arc.
c)With F as centre and radius 4.7cm, draw another arc which cuts arc of step (b) at point G.
d)Join EG and FG.
e)With G as centre and radius 5.2cm, draw an arc.
f)With E as centre and radius 4.7cm, draw another arc which intersects the arc drawn in step (e) at H.
g)Join HG and HE.
EFGH is the required parallelogram.