CBSE Class 11-science Answered
conic sections
Asked by gazalbhatnagar | 20 Feb, 2009, 07:18: PM
Expert Answer
let eqn is x2 + y2 +2gx + 2fy + c =0 it passes through (4,1) so we have 8g + 2f + c + 17 = 0 .....(1)
passes through (6,5) so we have 12g + 10 f + c + 61 = 0.........(2)
center (-g , -f ) on the line 4x + y = 16 ===> 4g + f = -16..........(3)
solving we get g = -3 , f = -4 , c = 15 and eqn as x2 + y2 - 6x - 8 y +15 = 0
Answered by | 20 Feb, 2009, 07:34: PM
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