Conclusions concerning the relation between electric fields and potential.
Asked by Jogy Jacob | 22nd Jun, 2013, 08:06: PM
1. By definition E = -dV/dr
V = -E.dr
V = -E*dr *cos(theta), where theta is the angle between the local electric field vector and displacement vector (dr)
Note that attains its most negative value when . In other words, the direction of the electric field at point corresponds to the direction in which the electric potential decreases most rapidly.
2. Electric field is perpendicular to the equipotential surface. And using the above formula,
E = -dV/dr
we can conclude, that the magnitude of the electric field is given by the change in potential per unit displament in the direction normal to the equipotential surface.
Answered by | 23rd Jun, 2013, 08:36: AM
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